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According to VSEPR theory, a molecule with the general formula AX2E (A is the central atom, X is the bonded atom and E is a lone pair of electrons) has how many regions of electron density around the central atom ? AX2E will have what kind of electronic geometry? AX2E will have what kind of molecular geometry?

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AX2E corresponds to a electronic geometry according to VSEPR theory is trigonal planar and the molecular geometry is bent as you can see in the image attached.

An example of this type of molecule is SO2. Where sulfur is the central atom, oxigen are bonded to sulfur and there is a lonely pair.

There is one region of electron density because the lonely pair. Nevertheless, tak into account the electronegativity of the atoms bonded in a particular case.

The bond angle for this type of molecule is approximately 120.

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A molecule of the sort AX2E has a trigonal planar electron geometry and a bent molecular geometry.

The shape of molecule is predicted on the basis of the valence shell electron pair repulsion theory. According to this theory, the number of electron pairs on the valence shell of the central atom in a molecule determines the shape of the molecule.

For a molecule of the sort AX2E, there are three electron domains around the central atom so the shape is based on a trigonal planar electron geometry and the molecule has two atoms so it has a bent molecular geometry.

Learn more: https://brainly.com/question/134058

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