Lance the Wizard has been informed that tomorrow there will be a 40% chance of encountering the evil Myrmidons and a 30% chance of meeting up with the dreadful Balrog. Moreover, Hugo the Elf has predicted that there is a 10% chance of encountering both tomorrow. What is the probability that Lance will be lucky tomorrow and encounter neither the Myrmidons nor the Balrog?

Respuesta :

Answer:

There is a 40% probability that Lance will be lucky tomorrow and encounter neither the Myrmidons nor the Balrog.

Step-by-step explanation:

We can solve this problem using the Venn's Diagram of these probabilities.

I am going to say that:

A is the probability that he encounters evil Myrmidons.

B is the probability that he encounters dreadful Balrog.

C is the probability that he does not encounter any of them.

We have that:

[tex]A = a + (A \cap B)[/tex]

In which a is the probability that he only encounter evil Myrmidons and [tex]A \cap B[/tex] is the probability that he encounters both.

By the same logic, we also have:

[tex]B = b + (A \cap B)[/tex]

The sum of all the probabilities is decimal 1, so:

[tex]a + b + (A \cap B) + C = 1[/tex]

We start finding these values from the intersection of both sets:

Hugo the Elf has predicted that there is a 10% chance of encountering both tomorrow.

This means that [tex]A \cap B = 0.1[/tex].

30% chance of meeting up with the dreadful Balrog.

This means that [tex]B = 0.3[/tex]

[tex]B = b + (A \cap B)[/tex]

[tex]0.30 = b + 0.10[/tex]

[tex]b = 0.20[/tex]

40% chance of encountering the evil Myrmidons

This means that [tex]A = 0.4[/tex]

[tex]A = a + (A \cap B)[/tex]

[tex]0.40 = a + 10[/tex]

[tex]a = 0.30[/tex]

What is the probability that Lance will be lucky tomorrow and encounter neither the Myrmidons nor the Balrog?

This probability is the value of C. So:

[tex]a + b + (A \cap B) + C = 1[/tex]

[tex]0.30 + 0.20 + 0.10 + C = 1[/tex]

[tex]C = 0.40[/tex]

There is a 40% probability that Lance will be lucky tomorrow and encounter neither the Myrmidons nor the Balrog.