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The vertices of a trapezoid are shown below.

P(0, 0), Q(3, 0), R(3, 6), S(0, 12)

This trapezoid is dilated about the origin by a scale factor of 4. What is the location of point S'?

Respuesta :

Ashraf82

The location of point S' is (0 , 48)

Step-by-step explanation:

The dilation in the coordinate plane use the origin (0 , 0) as the center

of the dilation and scale factor k, makes:

  • The x-coordinate of each point will multiply by k
  • The y-coordinate of each point will multiply by k

∵ the vertices of a trapezoid are:

→ P (0 , 0)

→ Q (3 , 0)

→ R (3 , 6)

→ S (0 , 12)

The trapezoid is dilated about the origin by a scale factor of 4

∵ The center of dilation is the origin (0 , 0)

∵ The scale factor = 4

- Each coordinate of its vertices will multiply by 4

∵ The coordinates of point S are (0 , 12)

∴ The coordinates of point S' = (0 × 4 , 12 × 4)

∴ The coordinates of point S' = (0 , 48)

The location of point S' is (0 , 48)

Learn more:

You can learn more about dilation in brainly.com/question/2480897

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