Answer:0.667 N
Explanation:
Given
It is noticed that Frictional Force is 0.2 N
Coefficient of kinetic Friction [tex]\mu _k=0.3[/tex]
We know Friction Force is given by
[tex]f_r=\mu _k\times Normal\ reaction[/tex]
therefore
[tex]0.2=\mu _k\times N[/tex]
[tex]0.2=0.3\cdot N[/tex]
[tex]N=\frac{0.2}{0.3}[/tex]
[tex]N=0.667 N[/tex]