Answer:
7l07 sec
Step-by-step explanation:
The pertinent equation is s(t) = -16t^2. We set this equal to zero to denote hammer hitting ground: -16t^2 = -50 ft. Solve for t^2 by dividing both sides by -16, obtaining
t^2 = 50 ft^2
The time required for the hammer to reach the ground is Sqrt(50 ft^2),
or 7.07 sec
