The new force of gravitational attraction is D. 20 newtons
Explanation:
The magnitude of the gravitational force between two objects is given by :
[tex]F=G\frac{m_1 m_2}{r^2}[/tex] (1)
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
m1, m2 are the masses of the two objects
r is the distance between them
In this problem, the initial gravitational force between the two objects A and B is
F = 5 N
When the distance between them is r.
Later, the distance is reduced in half:
[tex]r' = \frac{r}{2}[/tex]
Substituting into eq.(1), we see how does the force change:
[tex]F' = G\frac{m_1 m_2}{r'^2}=G\frac{m_1 m_2}{(r/2)^2}= 4 (G\frac{m_1 m_2}{r^2})=4F[/tex]
So, the force increases by 4 times. Therefore, the new force is
[tex]F'=4F=4(5 N) = 20 N[/tex]
Learn more about gravitational force:
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