Answer:
[tex]v = 21.33 m/s[/tex]
So the car was speeding more moving towards North
Explanation:
As we know that during the collision of two cars total momentum before collision and after collision must be conserved
So here we can say that after collision two cars are locked and moved together Exactly towards North-East
So here momentum of two cars must be exactly same before collision in East and North directions
So we will have
[tex]P_1 = P_2[/tex]
[tex]m_1v_1 = m_2v_2[/tex]
[tex]1600\times 16 = 1200 \times v[/tex]
[tex]v = 21.33 m/s[/tex]
So the car was speeding more moving towards North