Answer:
See diagram
Step-by-step explanation:
The line with the slope of [tex]-\dfrac{3}{2}[/tex] has the equation
[tex]y=-\dfrac{3}{2}x+b[/tex]
This line passes through the point (-1,2), so
[tex]2=-\dfrac{3}{2}\cdot (-1)+b\\ \\b=2-1.5\\ \\b=0.5[/tex]
The line has the equation
[tex]y=-1.5x+0.5[/tex]
This line intersects the y-axis at point (0,0.5) and the y-axis at point (1/3, 0). Plot these points and connect them with the straight line (see attached diagram)
