Answer:
0.15
Step-by-step explanation:
We have been given that the probability that it is Friday and that a student is absent is 0.03. Since there are five school days in a week, the probability that it is Friday is 0.2.
To solve the given problem, we will use conditional probability formula.
[tex]P(B|A)=\frac{P(A\text{ and }B)}{P(A)}[/tex], where,
P(B|A) = Probability of event B given A.
P(A and B) = Probability of event A and B.
P(A) = Probability of event A.
[tex]P(\text{Absent}|\text{Friday})=\frac{P(\text{Friday and absent})}{P(\text{Friday})}[/tex]
[tex]P(\text{Absent}|\text{Friday})=\frac{0.03}{0.2}[/tex]
[tex]P(\text{Absent}|\text{Friday})=\frac{3}{20}[/tex]
[tex]P(\text{Absent}|\text{Friday})=0.15[/tex]
Therefore, the probability, that a student is absent given that today is Friday, would be 0.15.