The temperature of the copper sample increases by [tex]172.9^{\circ}C[/tex]
Explanation:
When energy is supplied to a substance, the temperature of the substance increases according to the equation:
[tex]\Delta T = \frac{Q}{m C_s}[/tex]
where
[tex]\Delta T[/tex] is the increase in temperature
Q is the amount of energy supplied
m is the mass of the substance
[tex]C_s[/tex] is the specific heat capacity of the substance
For the sample of copper in this problem,
m = 538.0 g
Q = 8373 cal
[tex]C_s = 0.09 cal/gC[/tex]
Therefore, substituting we have:
[tex]\Delta T = \frac{8373}{(538.0)(0.09)}=172.9^{\circ}C[/tex]
Learn more about specific heat here:
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