Answer:
average force 377.67 N
linear impulse 318 kg.m/s
Explanation:
For the speed to increase from 0 to 5.3 m/s in 0.842 seconds. The constant acceleration is:
[tex]a = \frac{\Deltav}{t} = \frac{5.3 - 0}{0.842} = 6.3 m/s^2[/tex]
So the average force acting on the 60kg passenger is (according to Newton's 2nd law):
[tex]F = ma = 60*6.3 = 377.67 N[/tex]
The linear impulse experience by passenger within these seconds is
[tex]P = F\Deltat = 377.67*0.842 = 318 kg.m/s[/tex]
Answer:
a)318 b) 377.7
Explanation:
Since the passenger is in the bus, the passenger has the same acceleration with the bus and also the same speed with the car
Linear impulse = mass * change in velocity (Vf - Vi)
Vf = final velocity and Vi = initial velocity
Where m(mass) is the mass of the passenger,
Linear impulse = 60kg * (5.30 - 0) = 318 kgm/s
b) F( average) = m * acceleration
Acceleration = Vf - Vi/ t = 5.30 - 0 / 0.842
a = 6.295m/s2
F = 60 * 6.295
F = 377.7N
