Answer:
mass of hot water must be [tex]97.80[/tex]
Explanation:
The change of heat contained in hot and cold water will be the same.
Thus,
Δ[tex]q =[/tex]Δ[tex]-q[/tex]
Change in heat content is equal to the product of mass of the substance, specific heat capacity and change in temperature.
Substituting the given values in above relations, we get -
[tex]m_{hot}*c_{hot}*T_{hot} = m_{cold}*c_{cold}*T_{cold}\\[/tex]
C value is constant for water irrespective of water being hot or cold. So the formula becomes -
[tex]m_{hot}*T_{hot} = m_{cold}*T_{cold}[/tex]
[tex]m_{hot}*(37-51.6) = 85* (37 - 20.2) \\m_{hot} = 97.80[/tex]
Answer:
so 97.80 g mass of hot water must be added to reach 37.0°C
Explanation:
As we know
The specific heat capacity of liquid water is 4.184 J/gK)
mass cold water x specific heat x (Tfinal-Tinitial) + mass hot water x specific heat x (Tfinal-Tinitial) = 0
85 g x 4.184 J/gK) x( 37- 20.2) + mass of hot water x 4.184 J/gK) ( 37- 51.6)= 0
5974.752 + mass of hot water x (-61.086) = 0
5974.752 = - mass of hot water x (-61.086)
5974.752 = 61.086 mass of hot water
mass of hot water = 5974.752 / 61.086
mass of hot water = 97.80 g
so 97.80 g mass of hot water must be added to reach 37.0°C
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