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3. What is the concentration of glucose (C6H1206, MM - 180.16 g/mol) solution that was prepared by
dissolving 50.500 g of glucose in 500.0 mL of solution? Assume the solution has a density of 1.00
g/mL.

Respuesta :

nkirotedoreen46

Answer:

0.56 M

Explanation:

We are given;

Mass of glucose solute is 50.50 g

Volume of solution is 500 mL

We are required to calculate the concentration of glucose.

We need to know that, molarity is the concentration of a solution in moles per liter.

Molarity = Number of moles ÷ Molar mass

Step 1: Calculating the moles of glucose

Molar mass of glucose = 180.16 g/mol

Mass of glucose = 50.50 g

Therefore, Moles of Glucose = 50.50 g ÷ 180.16 g/mol

                                                = 0.280 Moles

Step 2: Molarity of glucose solution

We can use the formula to calculate the molarity of glucose solution

Moles of glucose = 0.280 moles

Volume of solution = 500 mL or 0.5 L

Molarity = 0.280 moles ÷ 0.5 L

             = 0.56 moles/L

             = 0.56 M

Therefore, the concentration of glucose is 0.56 M

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