In a physics lab, light with a wavelength of 490 nm travels in air from a laser to a photocell in a time of 16.6 ns. When a slab of glass with a thickness of 0.800 m is placed in the light beam, with the beam incident along the normal to the parallel faces of the slab, it takes the light a time of 21.0 ns to travel from the laser to the photocell. Use 3.00x108 m/s for the speed of light in a vacuum. Express your answer using two significant figures. O ? % AC 1 = 280 Submit Previous

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Answer:

The wavelength of the light in the glass is 182.9 nm.

Explanation:

Given that,

Wavelength = 490 nm

Time = 16.6 ns

Thickness = 0.800 m

Suppose, we need to find the wavelength of the light in the glass.

We need to calculate the distance

Using formula of distance

[tex]d=v\times t[/tex]

[tex]d=3\times10^{8}\times16.6\times10^{-9}[/tex]

[tex]d=4.98\ m[/tex]

After slab,

We need to calculate the time to cross air

Using formula of time

[tex]t=\dfrac{d}{v}[/tex]

Put the value into the formula

[tex]t=\dfrac{4.98-0.800}{3\times10^{8}}[/tex]

[tex]t=13.9\times10^{-9}\ s[/tex]

[tex]t=13.9\ ns[/tex]

So the time in slab is

[tex]t'=21.0-t[/tex]

Put the value into the formula

[tex]t'=21.0\ ns-13.9\ ns[/tex]

[tex]t'=7.1\ ns[/tex]

We need to calculate the speed in slab

Using formula of speed

[tex]v=\dfrac{0.8}{t'}[/tex]

Put the value into the formula

[tex]v=\dfrac{0.8}{7.1\times10^{-9}}[/tex]

[tex]v=1.12\times10^{8}\ m/s[/tex]

We need to calculate the wavelength

Using relation of wavelength and speed

[tex]\dfrac{c_{1}}{c_{2}}=\dfrac{\lambda_{1}}{\lambda_{2}}[/tex]

Put the value into the formula

[tex]\dfrac{3\times10^{8}}{1.12\times10^{8}}=\dfrac{490\times10^{-9}}{\lambda_{2}}[/tex]

[tex]\lambda_{2}=\dfrac{490\times10^{-9}\times1.12\times10^{8}}{3\times10^{8}}[/tex]

[tex]\lambda_{2}=182.9\ nm[/tex]

Hence, The wavelength of the light in the glass is 182.9 nm.