4 employees drive to work in the same car. the workers claim they were late to work because of a flat tire. their managers ask the workers to identify the tire that went flat; front drivers side, front passenger side, rear driver side, or rear passenger side. If the workers didn’t really have a flat tire and each randomly selects a tire, what is the probability that all 4 workers select the same tire

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Answer:

The required probability is 0.015625.

Step-by-step explanation:

Consider the provided information.

There number of tires are 4.

The number of workers are 4.

The probability that individual select front drivers side tire = [tex]\frac{1}{4}[/tex]

The probability that they all select front drivers side,tire is: [tex]\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}=\frac{1}{256}[/tex]

Similarly,

The probability that they all select front passenger side, tire is: [tex]\frac{1}{256}[/tex]

The probability that they all select rear driver side,tire is: [tex]\frac{1}{256}[/tex]

The probability that they all select rear passenger side, tire is: [tex]\frac{1}{256}[/tex]

Hence, the probability that all four workers select the same​ tire = [tex]\frac{1}{256}+ \frac{1}{256}+\frac{1}{256}+\frac{1}{256}[/tex]

the probability that all four workers select the same​ tire = [tex]\frac{4}{256}=\frac{1}{64}=0.015625[/tex]

Hence, the required probability is 0.015625.