Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

StartFraction S Over 2 pi r EndFraction equals h. – r = h
StartFraction S minus r Over 2 pi r EndFraction equals h. = h
S – S minus StartFraction r Over 2 pi EndFraction equals h. = h
S – S minus StartFraction 2 pi Over r EndFraction equals h. = h

Respuesta :

Answer:

Step-by-step explanation:

Only the term 2πrh contains h.  Isolate this term on the right by subtracting 2πr^2 from both sides:

S - 2πr^2 = 2πrh

Now divide the left side by 2πr, obtaining:

         s - 2πr^2

h =   ------------------

             2πr

Answer:

[tex]\frac{S - 2\pi r^{2}}{2\pi r} =h[/tex]

Step-by-step explanation:

The given equation is

[tex]S=2\pi rh+2\pi r^{2}[/tex]

Which is the equation of a surface area.

Marta is solving this equation for [tex]h[/tex], that means we need to isolate that variable.

First, we move the term nex to the one containing [tex]h[/tex]

[tex]S - 2\pi r^{2}=2\pi rh[/tex]

Second, we move all factors which are multiplying the variable [tex]h[/tex], they must pass to the other side of the equality as divisors,

[tex]\frac{S - 2\pi r^{2}}{2\pi r} =h[/tex]

Therefore, the result Marta should get is

[tex]\frac{S - 2\pi r^{2}}{2\pi r} =h[/tex]