Respuesta :
Answer:
The electric force between them if the pieces of grain are 2 cm apart is [tex]3.15\times 10^{-11}\textrm{ N}[/tex].
Explanation:
Given:
Charge on one grain, [tex]Q_{1}=6\times 10^{-10}\textrm{ C}[/tex]
Charge on another grain, [tex]Q_{2}=2.3\times 10^{-15}\textrm{ C}[/tex]
Separation between them, [tex]d=2\textrm{ cm}=0.02\textrm{ m}[/tex]
Electric force acting between two charges [tex]Q_{1}\textrm{ and }Q_{2}[/tex] separated by a distance [tex]d[/tex] is given as:
[tex]F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}[/tex]
Where, [tex]k[/tex] is Coulomb's constant equal to [tex]9\times 10^9\textrm{ }Nm^2/C^2[/tex].
Now, plug in all the values and solve for [tex]F{elec}[/tex].
[tex]F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}[/tex]
Therefore, the electric force between them if the pieces of grain are 2 cm apart is [tex]3.15\times 10^{-11}\textrm{ N}[/tex].
