Answer:
Interval=4.85±0.33
Interval (5.18,4.52)
Step-by-step explanation:
Consider the formula for the interval:
interval=[tex]X[/tex]±[tex]\frac{Z*S}{\sqrt{n} }[/tex]
Where:
X is the mean value
S is the standard deviation
n is the sample size
Z is the distribution
Alpha=1-0.95=0.05
[tex]Z_{alpha/2}=Z_{0.05/2} =Z_{0.025}[/tex]=1.96 (From Standard Z-Distribution Table)
Now use the above formula
interval=[tex]4.85[/tex]±[tex]\frac{1.96*0.79}{\sqrt{22} }[/tex]
Interval=4.85±0.33
Interval (5.18,4.52)
