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The eye color of mice is determined by a dominant allele E, corresponding to black eyes, and a recessive allele e, corresponding to red eyes. If two mice, one of genotype EE and the other of genotype ee, have offspring, compute the probability of one of the offspring having red eyes. Hint: Draw a Punnett square. (Enter the probability as a fraction.)

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MathPhys

Answer:

0

Step-by-step explanation:

Draw a Punnett square:

[tex]\left[\begin{array}{ccc}&E&E\\e&Ee&Ee\\e&Ee&Ee\end{array}\right][/tex]

There's only one possible genotype the offspring can have: Ee.  Since E is dominant, the offspring will have black eyes.  So the probability of one of the offspring having red eyes is 0.

Dominant alleles are the traits that are visible in an offspring while recessive traits are present on the genes as alleles but they get masked under the dominant trait.

The cross is between the eye colour of mice and the given genotypes are:

  • Dominant purebred = EE

  • Recessive purebred = ee

  • The F1 generation of the offspring can be determined by the Punnett square for which refer to the image attached below:

  • All the progenies produced in F 1 generation will be heterozygous dominant and will have black eyes.

Therefore, the probability of offspring having red eye colour would be 0 as no progenies produced have ee as the genotype.

To learn more about monohybrid cross follow the given link:

https://brainly.com/question/24076691

Ver imagen aliasger2709

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