A pyramid has a square base and four faces which are equilateral triangles. A charge Q is placed on the center of the base of the pyramid. What is the net flux of electric field ?e emerging from one of the triangular faces of the pyramid? Express your answer in terms of Q and ?0.

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Manetho Manetho · Answer 1 · 2019-11-15T11:34:03+01:00

Answer:

Φ=Q/8×ε_0

Explanation:

if we complete the Gaussian surface by attaching another pyramid of same specification by base to the original pyramid.

Then we have 8 identical triangular face.

Let the flux through 1 face is (Φ)

Therefore from 8 faces

8×(Φ)=Q/ε_0

therefore

or, Φ=Q/8×ε_0

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topeadeniran2 topeadeniran2 · Answer 2 · 2022-03-18T16:10:09+01:00

The computation shows that the net flux of the electric field is Φ=Q/8ε₀.

In this case, construct an eight faced closed surface consisting of two pyramids with the charge at the center.

By Gauss's law, the total flux will be Q/ε₀ since each face is identical, then the flux through each face is (1/8)th of the total flux.

Therefore, if we complete the Gaussian surface by attaching another pyramid, it will be:

8×(Φ) = Q/ε₀

Φ = Q/8ε₀

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