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The sum of three numbers is 70. One number is five more than a second number. It is also twice the third. Find the numbers.

Respuesta :

NosimpJamal
x+y+z=70
x=y+5
x=2z
y=x-5
(2z)+(x-5)+z=70
2z+2z-5+z=70
5z=75
z=15
x=2(15)
x=30
x=y+5
30=y+5
25=y
So the three numbers are 15, 25, and 30
SuperCatLover2000

Answer: 30, 25, and 15

Explanation:

Let the three numbers be a, b and c, so that a + b + c = 70

Because the first number is twice the third (and I am assuming that all three numbers are intergs), we can denote the first number by a =2k, the second by b = 2k-5 and the third by c = k

Then from your description

2k + (2k - 5) + k = 70

5k - 5 = 70

5k = 75

k = 15

2k = 30 2k-5 = 25

Hence the three numbers are a = 30, b = 25 and c = 15.

Hope this helps! :)

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