Answer:
The hotel bill in the first city before tax would be $ 650
Step-by-step explanation:
Let x be the hotel charges ( in dollars ) before tax in the first city,
∵ Hotel charges before tax in the second city were $1500 lower than in the first.
So, the hotel charges in second city = ( x - 1500 ) dollars,
Now, percentage of tax in,
First city = 8%
Second city = 10%,
So, the total tax in both city = 8% of x + 10% of (x-1500)
[tex]=\frac{8x}{100}+\frac{10(x-1500)}{100}[/tex]
[tex]=0.8x + 0.10(x-1500)[/tex]
According to the question,
[tex]0.8x + 0.10(x-1500)=435[/tex]
[tex]0.8x + 0.10x - 150 = 435[/tex]
[tex]0.9x = 435 + 150[/tex]
[tex]0.9x = 585[/tex]
[tex]\implies x = \frac{585}{0.9}=650[/tex]
Hence, the hotel bill in the first city before tax would be $ 650.
