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Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. In one day, 282 passes were sold for a total of $10,680. The following system of equations models this scenario:

50x + 20y = 10,680
x + y = 282

How many unlimited-ride passes were sold?

Respuesta :

CPED

Answer:

The  unlimited-ride passes sold are equal to 168

Step-by-step explanation:

According to given scenario:

x = unlimited-ride passes

y = entrance-only pass

Given that:

50x + 20y = 10,680  -------- eq1

x + y = 282  ------------ eq2

From eq2:

x = 282 - y

Putting value of x  in eq1:

50(282 - y) + 20y = 10,680

By simplifying:

14,100 - 50y + 20y = 10,680

14,100 - 30y = 10,680

30y = 14,100 - 10680

30y = 3,480

Dividing both sides by 30

y = 114

Now put value of y in eq2:

x + 114 = 282

x = 282 - 144

x = 168

So, the  unlimited-ride passes sold are equal to 168

i hope it will help you!

Answer:

option c

Step-by-step explanation:

The  unlimited-ride passes sold are equal to 168 so therefor it is c

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