Respuesta :
Answer :
(1) The hybridization of central atom beryllium in [tex]BeCl_2[/tex] is, [tex]sp[/tex]
(2) The hybridization of central atom nitrogen in [tex]NO_2[/tex] is, [tex]sp^2[/tex]
(3) The hybridization of central atom carbon in [tex]CCl_4[/tex] is, [tex]sp^3[/tex]
(4) The hybridization of central atom xenon in [tex]XeF_4[/tex] is, [tex]sp^3d^2[/tex]
Explanation :
Formula used :
[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
Now we have to determine the hybridization of the following molecules.
(1) The given molecule is, [tex]BeCl_2[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [2+2]=2[/tex]
The number of electron pair are 2 that means the hybridization will be [tex]sp[/tex] and the electronic geometry of the molecule will be linear.
(2) The given molecule is, [tex]NO_2[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [4]=2[/tex]
If the sum of the number of sigma bonds, lone pair of electrons and odd electrons present is equal to three then the hybridization will be, [tex]sp^2[/tex].
In nitrogen dioxide, there are two sigma bonds and one lone electron pair. So, the hybridization will be, [tex]sp^2[/tex].
(3) The given molecule is, [tex]CCl_4[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [4+4]=4[/tex]
The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.
(4) The given molecule is, [tex]XeF_4[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [8+4]=6[/tex]
Bond pair electrons = 4
Lone pair electrons = 6 - 4 = 2
The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.
But as there are four atoms around the central xenon atom, the fifth and sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square planar.
Hybridization refers to the mixing of atomic orbitals in order to obtain hybrid orbitals suitable for bonding.
Hybridization is a valence bond idea. It implies the mixing up of orbitals of appropriate energy to yield hybrid orbitals which are suitable for bonding. The number of atomic orbitals that are combined is equal to the number of hybrid orbitals obtained.
- The central atom in beryllium chloride is Be, the Be atom is sp hybridized in BeCl2.
- The central atom in nitrogen dioxide (NO2)is nitrogen, the nitrogen atom is sp2.
- The central atom in carbon tetracchloride is carbon. Carbon is sp3 hybridized.
- The central atom in xenon tetrafluoride is xenon. Xenon is sp3d2 hybridized in the compound.
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