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An object is thrown off a cliff with a horizontal speed of 16.8 m/s. After 5.60 seconds, the object hits the ground. Find the height of the cliff.

Respuesta :

MathPhys

Answer:

154 m

Explanation:

Given (in the y direction):

v₀ = 0 m/s

a = 9.8 m/s²

t = 5.60 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (5.60 s) + ½ (9.8 m/s²) (5.60 s)²

Δy = 154 m

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