Answer: V1 = 45.6 ml
Explanation:
This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.
The dilution equation will be used. The equation is as follows:
M1V1 = M2V2 where
V1 = Initial volume of phosphate solution.
M1 = Initial concentration of phosphate solution.
V2 =Final volume of phosphate solution.
M2 = Final concentration of phosphate solution .
From the information given,
M1 = 4.5
V1 = ?
M2 = 2.0
V2 = 80
4.5 × V1 = 2×80
4.5V1 = 160
V1 = 160/4.5
= 35.6 ml
The volume of a 4.5 m solution of phosphate that will be necessary to create a 80.0 ml stock of 2.0 m phosphate solution would be 35.56 mL
According to the dilution principle, the number of moles of a solution before and after dilution is conserved.
Mathematically, M1V1 = M2V2
In this case, M1 = 4.5M, V1 = ?, V2 = 80.0 mL, and M2 = 2.0 M
V1 = M2V2/M1
= 2 x 80/4.5
= 35.56 mL
More on dilution principle can be found here: https://brainly.com/question/11493179
