Answer:
The correct answer is option D.
Explanation:
Mass of compound = 42.0 g
Mass of carbon in compound = 36.0 g
Mass of hydrogen in compound = 6.0 g
Moles of carbon = [tex]\frac{36.0 g}{12 g/mol}=3.0 mol[/tex]
Moles of hydrogen = [tex]\frac{6.0 g}{1 g/mol}=6.0 mol[/tex]
Empirical formula of the compound, divide least number of moles from each element.
Carbon = [tex]\frac{3.0}{3.0}=1[/tex]
Hydrogen = [tex]\frac{6.0}{3.0}=2[/tex]
Empirical formula of compound = [tex]CH_2[/tex]
The empirical formula of the compound can be calculated from the given data.
