Answer:
a) 15 m/s
b) 11.25 m
Explanation:
a) when the rocket is approaching to the maximum height , its velocity =0 (assume g= 10 m/s² downwards)
applying motion equations upwards
V = U +at
0 = U + (-10)*1.5
U = 15 m/s (initial velocity)
b) let maximum height be S and V =0 (velocity at highest point)
V² = U² + 2aS
0 = 15² + 2 * (-10)*S
S = 11.25 m