4. An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5
m/s? over a distance of 20 m. What is its new velocity?

Respuesta :

Answer:

11.9 m/s

*But if you need the answer with sig figs it should be 10m/s (1sf) or 12m/s (2sf)

Explanation:

[tex]{vf}^{2} - {vi}^{2} = 2ad[/tex]

[tex] {vf}^{2} = 2ad + {vi}^{2} [/tex]

[tex] {vf}^{2} = 2 \times 1.5 \times 20 + {9}^{2} [/tex]

[tex] {vf}^{2} = 60 + 81[/tex]

[tex] {vf}^{2} = 141[/tex]

[tex]vf = \sqrt{141} [/tex]

[tex]vf = 11.874[/tex]

best answer if it worked