Answer:
33.5 kJ
Explanation:
here there is no difference is made in the temperature. Only thing happens here is the conversion of the ice in to water of 0 degree. The heat energy taken from the outside is spent for this conversion.
we have ice 100g =0.1 kg
Appplying Q=mL
Q= [tex]0.1 kg * 335 000 J kg^{-1}[/tex]
Q = 33 500 J
Q = 33.5 kJ