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You shine light with a wavelength of 400 nm at two small slits (I and II) and observe an interference pattern on a screen. What is the difference in path lengths between the light that travels from slit I to the first dark fringe of the pattern and the light that travels from slit II to the same dark fringe?

Respuesta :

Answer:

2 x 10⁻⁷ m

Explanation:

Since the light from two slits interfere to form dark fringe on the screen ,

the path difference must be odd multiple of λ / 2 .

Since it is the first dark fringe the factor of odd multiple must be one.

So path difference must be

( 2n +1 ) x λ / 2 .

for first dark fringe

n = 0

path difference  =  λ / 2

400 x 10⁻⁹ / 2 m

= 2 x 10⁻⁷ m

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