Answer:
SiC=169.26 Mpa
Partially stabilized zirconia=507.77 Mpa
Explanation:
SiC
Stress intensity, K is given by
[tex]K=\sigma Y\sqrt{\pi a}[/tex] hence making [tex]\sigma[/tex] the subject where [tex]\sigma[/tex] is applied stress, Y is shape factor, a is crack length
[tex]\sigma=\frac {K}{Y\sqrt{\pi a}}[/tex] substituting the given figures and assuming shape factor, Y of 1
[tex]\sigma=\frac {3}{1\sqrt{\pi 100*10^{-6}}}= 169.2569\approx 169.26 Mpa[/tex]
Stabilized zirconia
Stress intensity, K is given by
[tex]K=\sigma Y\sqrt{\pi a}[/tex] hence making [tex]\sigma[/tex] the subject where [tex]\sigma[/tex] is applied stress, Y is shape factor, a is crack length
[tex]\sigma=\frac {K}{Y\sqrt{\pi a}}[/tex] substituting the given figures and assuming shape factor, Y of 1
[tex]\sigma=\frac {9}{1\sqrt{\pi 100*10^{-6}}}= 507.7706\approx 507.77 Mpa[/tex]