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A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some instant in time.
Part A What will be the induced magnetic field strength 7.0 cm radially outward from the center of the plates?
Part B

What will be the value of the field strength after the capacitor is fully charged?

Express your answer with the appropriate units.

Respuesta :

usamakld99

Answer:

[tex]B= 1.14 X 10^{-7} Tesla[/tex]

Explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as

        [tex]B=\frac{I\mu}{2r\pi}[/tex]

        [tex]B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}[/tex]

      [tex]B= 1.14 X 10^{-7} Tesla[/tex]

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

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