Answer:
0.0010,0.2743
Step-by-step explanation:
Given that Stanford–Binet IQ Test scores are normally distributed with a mean score of 100 and a standard deviation of 15
If x represents the scores then
X is N(100,15)
a) See enclosed file
b) Z score =[tex]\frac{x-100}{15}[/tex]
c) the probability that a randomly selected person has an IQ test score
i. Over 145.
=[tex]P(X>145) = P(Z>3) = 0.0010[/tex]
ii. Under 91
=[tex]P(X<91) = P(Z<-0.6)\\= 0.2743[/tex]