Answer:
1.03882464 Joules
2.07764928 Joules
Explanation:
k = Spring constant = 252 Nm
x = Distance compressed = 0.0908 m
Potential energy of the spring
[tex]P=\frac{1}{2}kx^2\\\Rightarrow P=\frac{1}{2}\times 252\times 0.0908^2\\\Rightarrow P=1.03882464\ J[/tex]
Work done by the spring is 1.03882464 Joules
Force on spring
[tex]F=kx\\\Rightarrow F=252\times 0.0908\\\Rightarrow F=22.8816\ N[/tex]
Work done
[tex]W=F\times s\\\Rightarrow W=22.8816\times 0.0908\\\Rightarrow W=2.07764928\ J[/tex]
Work done by the applied force is 2.07764928 Joules
