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1. A surfer moving with an initial speed of 1.5 m/s catches a wave and accelerates at a constant
rate of 2.1 m/s2 for 2.2 s.
a) How far does the surfer travel in those 2.2 seconds?
b) What's the velocity of the surfer at the end of those 2.2 seconds?

Respuesta :

MathPhys

Answer:

a) Δx ≈ 8.4 m

b) v ≈ 6.1 m/s

Explanation:

Given:

v₀ = 1.5 m/s

a = 2.1 m/s²

t = 2.2 s

a) Find: Δx

Δx = v₀ t + ½ at²

Δx = (1.5 m/s) (2.2 s) + ½ (2.1 m/s²) (2.2 s)²

Δx ≈ 8.4 m

b) Find: v

v = at + v₀

v = (2.1 m/s²) (2.2 s) + (1.5 m/s)

v ≈ 6.1 m/s

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