Respuesta :
Answer:
Measures equal or lower than 19.94 inches are significantly low.
Measures equal or higher than 25.06 inches are significantly high.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 22.5, \sigma = 1.1[/tex]
Find the back-to-knee lengths separating significant values from those that are not significant.
Significantly low
In this exercise, a value is going to be to significantly low if it has a pvalue of 0.01 or less. So we have to find X when Z has a pvalue of 0.01. This is between [tex]Z = -2.32[/tex] and [tex]Z = -2.33[/tex], so we use [tex]Z = -2.325[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2.325 = \frac{X - 22.5}{1.1}[/tex]
[tex]X - 22.5 = -2.325*1.1[/tex]
[tex]X = 19.94[/tex]
Measures equal or lower than 19.94 inches are significantly low.
Significantly high
In this exercise, a value is going to be to significantly high if it has a pvalue of 0.99 or more. So we have to find X when Z has a pvalue of 0.99. This is [tex]Z = 2.325[/tex]. So:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2.325 = \frac{X - 22.5}{1.1}[/tex]
[tex]X - 22.5 = 2.325*1.1[/tex]
[tex]X = 25.06[/tex]
Measures equal or higher than 25.06 inches are significantly high.