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A chemical reaction takes place in a container of cross-sectional area 50 cm2. As a result of the reaction, a piston is pushed out through 15 cm against an external pressure of 121 kPa. Calculate the work done by the system. (3 sig figs, answer in J) Before starting the calculation, be sure to ask yourself whether or not this is a reversible process. Question 1 options:

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Answer:

-90.8 Joules

Explanation:

A = Area of container = 50 cm²

d = Length pushed = 15 cm

P = External Pressure = 121 kPa

Change in volume

[tex]\Delta v=Ad\\\Rightarrow \Delta v=50\times 15\\\Rightarrow \Delta v=750\ cm^3\\\Rightarrow \Delta v=750\times 10^{-6}\ m^3[/tex]

Work done

[tex]W=-P\Delta v\\\Rightarrow W=-121\times 10^3\times 750\times 10^{-6}\\\Rightarrow W=-90.75=-90.8\ J[/tex]

Work done by the system is -90.8 Joules

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