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Consider a wildflower population with the following allele and genotype frequencies. Frequency of the CR allele: p = 0.6 Frequency of the CW allele: q = 0.4 Frequency of CRCR : 50% Frequency of CRCW : 20% Frequency of CWCW : 30% Is this population in Hardy-Weinberg equilibrium?

Respuesta :

Diatonic254

NO,  It Isn't

Ideally a population in Hardy Weinberg equilibrium should hold true to the following equation for genotypic frequencies of an allele;

P² + 2pq + q² = 1

Explanation:

We are provided with allelic frequencies hence we can derive the genotypic frequencies; (CR allele: p = 0.6 Frequency of the CW allele: q = 0.4)

P² = 0.6 ^2 = 0.36

2pq = 2 * 0.6 * 0.4 = 0.48

q² = 0.4 ^ 2 = 0.16

Lets find out if all add up to  as supposed to;

0.36 +  0.48 + 0.16 = 1

Converting to percentages is easy – just multiply by 100

  • 36 % CRCR
  • 48% CRCW
  • and 16 % CWCW

The population provided is not in equilibrium because their percentages vary widely to that the expected Hardy Weinberg's equilibrium percentages. This could be attributed to factors like;

  1. Migration
  2. Mutations,
  3. There is natural selection in progress in the population
  4. There is gene flow

Learn More:

For more on Hardy Weinberg's equilibrium  check out;

https://brainly.com/question/9916141

#LearnWithBrainly

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