For each of the following unbalanced equations, calculate how many grams of each product would be produced by complete reaction of 10.8 g of the second reactant. (a) S(s) + H2SO4(aq) → SO2(g) + H2O(l) SO2 WebAssign will check your answer for the correct number of significant figures. g H2O WebAssign will check your answer for the correct number of significant figures. g

Respuesta :

Answer:

[tex]10.6g[/tex] of [tex]SO_{2}[/tex]

[tex]2.0g[/tex] of [tex]H_{2}O[/tex]

Explanation:

First we are going to balance the reaction:

[tex]S+_{2}H_{2}SO{4}=_{3}SO_{2}+_{2}H_{2}O[/tex]

Then we are going to find the quantities with the stoichiometry:

-For [tex]SO_{2}[/tex]:

[tex]10.8gH_{2}SO_{4}*\frac{1molH_{2}SO_{4}}{98.079gH_{2}SO_{4}}*\frac{3molesSO_{2}}{2molesH_{2}SO_{4}}*\frac{64.066gSO_{2}}{1molSO_{2}}=10.6gSO_{2}[/tex]

-For [tex]H_{2}O[/tex]:

[tex]10.8gH_{2}SO_{4}*\frac{1molH_{2}SO_{4}}{98.079gH_{2}SO_{4}}*\frac{2molesH_{2}O}{2molesH_{2}H_{2}O}*\frac{18.015gH_{2}O}{1molH_{2}O}=10.6gH_{2}O=2.0gH_{2}O[/tex]