Answer:
[tex]\dfrac{1}{3}x+5=23[/tex]
Step-by-step explanation:
Let f represent the weight of Luisa’s dog.
Fabiola’s dog is 5 pounds heavier than one-third of the weight of Luisa’s dog.
Luisa' dog weight: x pounds
One-third of the weight of Luisa’s dog: [tex]\dfrac{1}{3}x[/tex] pounds
5 pounds heavier than one-third of the weight of Luisa’s dog: [tex]\dfrac{1}{3}x+5[/tex] pounds
Fabiola's dos weight: [tex]\dfrac{1}{3}x+5[/tex] pounds that is 23 pounds.
Hence,
[tex]\dfrac{1}{3}x+5=23[/tex]
Solve it:
[tex]\dfrac{1}{3}x+5=23\\ \\\dfrac{1}{3}x+5-5=23-5\\ \\\dfrac{1}{3}x=18\\ \\x=3\cdot 18=54\ pounds[/tex]
