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Error Analysis Describe and correct the error
student made when solving. kx + 3x = 4 for x.

kx + 3x = 4
kx + 3x - 3x = 4 - 3x
kx=4 - 3x
- 3x
x = 4*3* X​

Respuesta :

davidlcastiblanco

Answer:

Solving [tex]kx+3x=4[/tex]

for x

[tex]x=\frac{4}{k+3}[/tex]

Step-by-step explanation:

[tex]kx+3x=4[/tex]

[tex]kx+3x-3x=4-3x[/tex] here the student leave 'x' in both sides

The error is not notice the factor is the 'x'

So:

[tex]kx+3x=4[/tex]

[tex]x(k+3)=4\\x=\frac{4}{k+3}[/tex]

Is the best way to solving to 'x' 'k' maybe is knowing o is a constant

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