Answer:
56.6 m/s
Explanation:
The velocity of an object accelerating at constant acceleration is given by the following SUVAT equation
[tex]v(t)=u+at[/tex]
where
u is the initial velocity
a is the acceleration
t is the time
For the object in the problem,
u = 0 since it starts from rest
[tex]a=4.6 m/s^2[/tex] is the acceleration
Substituting t = 12.3 s, we find the velocity at that time:
[tex]v=0+(4.6)(12.3)=56.6 m/s[/tex]
