Answer:
4.4 km
Explanation:
t = Time taken
u = Initial velocity = 24 m/s (Assumed)
v = Final velocity
s = Displacement
a = Acceleration = -0.065 m/s² (Assumed)
Distance = Speed × Time
[tex]\text{Distance}=24\times 400=9600\ m[/tex]
The train travels for 9600 m.
[tex]v=u+at\\\Rightarrow 0=24-0.065t\\\Rightarrow t=\frac{-24}{-0.065}=369.23\ s[/tex]
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s=24\times 369.23+\frac{1}{2}\times -0.065\times 369.23^2\\\Rightarrow s=4430.76\ m[/tex]
The Distance the train traveled when it slowed down is 4.4 km