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Imagine an aluminum cup of 0.30 liter capacity filled with mercury at 14.0 degrees C. How much mercury, if any, will spill out of the cup if the temperature is raised to 27.0 degrees C? The coefficient of volume expansion of mercury is 1.8 E-04/ degree C. Express your answer in cubic centimeters.

Respuesta :

Answer:

ΔV=0.00043 L

Explanation:

Given that

V= 0.3 L

T= 14 °C

T'=27°C

Coefficient of volume expansion

[tex]\beta _{mercury}=1.8\times 10^{-4}\ C^{-1}[/tex]

[tex]\beta _{Almunium}=0.69\times 10^{-4}\ C^{-1}[/tex]

[tex]\Delta V=(\beta _{mercury}-\beta _{Almunium} )V\Delta T[/tex]

[tex]\Delta V=(1.8\times 10^{-4} - 0.69\times 10^{-4})\times 0.3\times (27-14)[/tex]

ΔV=0.00043 L

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