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A 18.0 kg child descends a slide 3.40 m high and reaches the bottom with a speed of 2.48 m/s. How much thermal energy due to friction was generated in this process?

Respuesta :

MathPhys

Answer:

544 J

Explanation:

Potential energy at top = kinetic energy at bottom + work done by friction

PE = KE + W

mgh = ½ mv² + W

W = mgh − ½ mv²

Given m = 18.0 kg, h = 3.40 m, and v = 2.48 m/s:

W = (18.0 kg) (9.8 m/s²) (3.40 m) − ½ (18.0 kg) (2.48 m/s)²

W = 544 J

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