Answer:
The answer is 75.4 meters
Explanation:
The car is traveling with constant velocity, when the car stop the fritcion force will reduce the velocity to zero, so:
[tex]Fr=-uk*mg\\Fr=0.178*mc*9.81=mc*1.74N\\ar=\frac{mc*1.74N}{mc}\\ar=1.74m/s^2[/tex]
so using the accelerated motion formulas:
[tex]vf^2=vo^2+a*d\\[/tex]
[tex]vo=58.2km/h*\frac{1h}{3600s}*\frac{1000m}{1km}=16.2m/s[/tex]
[tex]0=(16.2m/s)^2-2*(1.74m/s^2)*d\\d=75.4m[/tex]
