Explanation:
Given:
v₀ = 22 m/s
v = 0 m/s
t = 17.32 s
Find: a
v = at + v₀
(0 m/s) = a (17.32 s) + (22 m/s)
a = -1.270 m/s²
Round as needed.
Answer:
A truck traveling with an initial velocity of 22 m/s comes to a stop in 17.32 sec, the acceleration of the truck is [tex]- 1.27 m/s^2[/tex]
Explanation
From the Given statements, we know that Initial Velocity (u) = 22 m/s
time (t) = 17.32 seconds
Final Velocity (v) = 0 m/s [ because the truck Stops]
find acceleration on Applying the Equation of Motion
v = u + at
substituting the values in above equation, we find
a =[tex]\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}[/tex]
=[tex]\frac{0-22}{17.32} \mathrm{m} / \mathrm{s}^{2}[/tex]
a = [tex]- 1.27 m/s^2[/tex] [negative sign shows reverse direction]
