Respuesta :
Answer:
Actual yield = 0.1791 moles
Theoretical yield in moles = 0.644 moles
Percent yield = 27.8 %
Explanation:
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Given: For Fe
Given mass = 10.0 g
Molar mass of Fe = 55.845 g/mol
Moles of Fe = 10.0 g / 55.845 g/mol = 0.1791 moles
So, Actual yield = 0.1791 moles
Given, Moles of [tex]Fe_2O_3[/tex] = 0.322 moles
According to the given reaction:
[tex]Fe_2O_3+3C\rightarrow 2Fe+3CO[/tex]
1 mole of [tex]Fe_2O_3[/tex] on reaction produces 2 moles of Fe
0.322 mole of [tex]Fe_2O_3[/tex] on reaction produces 2*0.322 moles of Fe
Actual moles of Fe produced = 0.644 moles
Theoretical yield in moles = 0.644 moles
Or, Mass of iron = Moles × Molar mass = 0.644 × 55.845 g = 35.96 g
Theoretical yield = 35.96 g
Given experimental yield = 10.0 g
% yield = (Experimental yield / Theoretical yield) × 100 = (10.0/35.96) × 100 = 27.8 %
When 0.322 mole of F₂O₃ react with with excess carbon (C), the actual yield in mole, the theoretical yield in mole and the percentage yield are:
1. The actual yield of iron (Fe) in mole is 0.179 mole
2. The theoretical yield of iron (Fe) in mole is 0.644 mole
3. The percentage yield of iron (Fe) is 27.8%
1. Determination of the actual yield in mole.
Mass of Fe = 10 g
Molar mass of Fe = 56 g/mol
Mole of Fe =?
Mole = mass / molar mass
Mole of Fe = 10 / 56
Mole of Fe = 0.179 mole
Thus, the actual yield of Fe in mole is 0.179 mole
2. Determination of the theoretical yield of Fe.
The balanced equation for the reaction is given below:
F₂O₃ + 3C —> 2Fe + 3CO
From the balanced equation above,
1 mole F₂O₃ of reacted to produce 2 moles of Fe.
Therefore,
0.322 mole of F₂O₃ will react to produce = 2 × 0.322 = 0.644 mole of Fe.
Thus, the theoretical yield of Fe in mole is 0.644 mole
3. Determination of the percentage yield
Actual yield of Fe = 0.179 mole
Theoretical yield of Fe = 0.644 mole
Percentage yield =?
[tex]Percentage = \frac{Actual}{Theoretical} * 100\\\\= \frac{0.179}{0.644} * 100[/tex]
Percentage yield = 27.8%
Therefore, the percentage yield of Fe is 27.8%
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