Answer:
the answer is 17
Step-by-step explanation:
juans free throw % is 65 so botina has to make 17 out of 25 to get a better percent which is 68
ANSWER:
Botina has to make 17 successful attempts out of 25 attempts.
SOLUTION:
Given, Juan made 13 out of 20 free throws.
Botina shoots 25 free throws,
We need find what's the minimum number she has to make in order to have a better free-throw percentage than Juan?
Let, the minimum number of successful throws be x.
Now, percentage of Botina should be greater than percentage of jaun
Percentage of Botina > percentage of Jaun
[tex]\begin{array}{l}{\frac{\text {number of successful attempts by botina}}{\text {total number of attempts by botina}} \times} {100>\frac{\text {number of successful atempts by jaun}}{\text {total number of attempts by jaun}} \times 100}\end{array}[/tex]
[tex]\begin{array}{l}{\frac{x}{25} \times 100>\frac{13}{20} \times 100} \\\\ {\frac{x}{25}>\frac{13}{20}} \\\\ {x>25 \times \frac{13}{20}} \\\\ {x>5 \times \frac{13}{4}} \\\\ {x>\frac{65}{4}} \\\\ {x>16.25}\end{array}[/tex]
As the number of attempts cannot be in decimal values, we have to consider the integer above 16.25 i.e. 17
Hence, botina has to make 17 successful attempts.
